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1z0-071證照信息將是您最好的助力Oracle Database SQL

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最新的 Oracle PL/SQL Developer Certified Associate 1z0-071 免費考試真題 (Q85-Q90):

問題 #85
Which three queries execute successfully?

A. SELECT 1 / SYSDATE - DATE '2019-01-01' FROM DUAL;
B. SELECT SYSDATE - DATE '2019-01-01' - 1 FROM DUAL;
C. SELECT (SYSDATE-DATE '2019-01-01') / 1 FROM DUAL;
D. SELECT 1 - SYSDATE- DATE '2019-01-01' FROM DUAL;
E. SELECT SYSDATE / DATE '2019-01-01' - 1 FROM DUAL
F. SELECT SYSDATE - 1 - DATE'2019-01-01' EROM DUAL;

答案：B,C,F

解題說明：
In Oracle SQL, date arithmetic can be performed directly, subtracting one date from another to get the number of days between them:
* Option A:
* SELECT (SYSDATE - DATE '2019-01-01') / 1 FROM DUAL; This query successfully calculates the difference between the current date and a specific date.
* Option D:
* SELECT SYSDATE - DATE '2019-01-01' - 1 FROM DUAL; This query subtracts a specific date from the current date and then subtracts 1 more day, which will execute successfully.
* Option F:
* SELECT SYSDATE - 1 - DATE '2019-01-01' FROM DUAL; Similar to D, this will successfully compute the date difference minus one day.
Options B, C, and E are incorrect because:
* Option B and Option C: You cannot divide by a date or divide a date by a number.
* Option E: You cannot subtract a date from a number.

問題 #86
You execute these commands:
SQL> DEFINE hiredate = '01-APR -2011';
SQL> SELECT employee_id, first_name, salary FROM employees WHERE hire date > &hiredate AND manager_id >&mgr_id; For which substitution variables will you be prompted?

A. none
B. &hiredate and &mgr_id
C. only &hiredate
D. only &mgr_id

答案：D

問題 #87
View the Exhibit and examine the structure of the EMPLOYEES table.
You want to display all employees and their managers having 100 as the MANAGER_ID.
You want the output in two columns: the first column would have the LAST_NAME of the managers and the second column would have LAST_NAME of the employees.

Which SQL statement would you execute?

A. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE e.managerjd=100;
B. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
WHERE m.employee_id = e.manager_id AND e.managerjd=100;
C. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON e.employee_id = m.manager_id
WHERE m.manager_id=100;
D. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE m.manager_id=100;

答案：A

問題 #88
An Oracle database server session has an uncommitted transaction in progress which updated 5000 rows in a table.
In which three situations does the transact ion complete thereby committing the updates?

A. When a DBA issues a successful SHUTDOWN TRANSACTIONAL statement and the user, then issues a COMMIT
B. When a CREATE INDEX statement is executed successfully in same session
C. When a CREATE TABLE AS SELECT statement is executed unsuccessfully in the same session
D. When the session logs out is successfully
E. When a COMMIT statement is issued by the same user from another session in the same database instance
F. When a DBA issues a successful SHUTDOWN IMMEDIATE statement and the user then issues a COMMIT

答案：A,B,D

問題 #89
Which two statements are true about INTERVAL data types?

A. The value in an INTERVAL DAY TO SECOND column can be copied into an INTERVAL YEAR TO MONTH column.
B. The YEAR field in an INTERVAL YEAR TO MONTH column must be a positive value.
C. INTERVAL YEAR TO MONTH columns only support monthly intervals within a single year.
D. INTERVAL YEAR TO MONTH columns support yearly intervals.
E. INTERVAL DAY TO SECOND columns support fractions of seconds.
F. INTERVAL YEAR TO MONTH columns only support monthly intervals within a range of years.

答案：E,F

問題 #90
......

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